4n^2+80n+400=0

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Solution for 4n^2+80n+400=0 equation: 



4n^2+80n+400=0

a = 4; b = 80; c = +400;
Δ = b2-4ac
Δ = 802-4·4·400
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$n=\frac{-b}{2a}=\frac{-80}{8}=-10$

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